OpenCV中度角拟合方法

_Assert(count> 0); double x = 0, y = 0, x2 = 0, y2 = 0, xy = 0, w = 0; double dx2, dy2, dxy; int i; float t; // Calculating the erage of x and y... if( weights == 0 ) { for( i = 0; i < count; i += 1 ) { x += points[i].x; y += points[i].y; x2 += points[i].x * points[i].x; y2 += points[i].y * points[i].y; xy += points[i].x * points[i].y; } w = (float) count; } else { for( i = 0; i < count; i += 1 ) { x += weights[i] * points[i].x; y += weights[i] * points[i].y; x2 += weights[i] * points[i].x * points[i].x; y2 += weights[i] * points[i].y * points[i].y; xy += weights[i] * points[i].x * points[i].y; w += weights[i]; } } x /= w; y /= w; x2 /= w; y2 /= w; xy /= w; dx2 = x2 - x * x; dy2 = y2 - y * y; dxy = xy - x * y; t = (float) atan2( 2 * dxy, dx2 - dy2 ) / 2; line[0] = (float) cos( t ); line[1] = (float) sin( t ); line[2] = (float) x; line[3] = (float) y;}

3，案例：圆周最优

有如下的原左图：

通过OpenCV的东北方傅立叶，骨架浓缩，然后再圆周最优，用作DIST_L1获得的结果如下：

OpenCV-C++/Python视频教程30课堂，请看B车站：

(python版本) (C++版本)

THE END

文章来源：OpenCV学堂

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